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orAClE hAving Count

譬如如下数据 id value 1 2 1 3 2 3 3 5 3 6 可以写个语句统计value的分组 select id,sum(value) from table group by id having sum(value)>=5 这样的结果就是 1 5 3 11 其实这句的意思就是 select id,sum(value) from table where sum(value)>...

--1,查询hm有重复的记录select hm,count(*) from a group by hm having count(*)>1--2,查询hm和xm都有重复select hm,xm count(*) from a group by hm,xm having count(*)>1

select a,count(*) from table group by a having count(*)>1 嗯。是的。这样是查出来该字段重复2次以上的列。

sql查找一列中某一数值出现次数大于2的记录select 用户id from 表名 where 评分=2 group by 用户id having count(评分)>=2unionselect 用户id from 表名 ...

select tabtype,count(*) from tab where onwer='abcde' group by tabtype having count(*) > 2

61=C或D 62=C SELECT Sno , AVG(Grade) FROM SC GROUP BY Sno HAVING COUNT(Sno)>1;

where 对 表中已有的字段数据进行筛选; having 对聚合函数(count,sum,max,avg等)产生的数据进行筛选;

加个where 条件不行么,where status 0 如果不行的话,就写子查询, 先筛选where status 0 再group by

select testid,count(1) from testtable group by testid having count(1)>1count(1)就是重复在数量

如果两列数据重复的话,可以通过count方法,找出计算条数大于1的,那么表示此条数据重复: sql: select district(*) from products having count(*)>1; 备注:实际上两列重复的话,都是针对某个字段比较有意。 sql:select name,count(*) from us...

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